-[3z-(11z+3)]=3+(7z+1)

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Solution for -[3z-(11z+3)]=3+(7z+1) equation:


Simplifying
-1[3z + -1(11z + 3)] = 3 + (7z + 1)

Reorder the terms:
-1[3z + -1(3 + 11z)] = 3 + (7z + 1)
-1[3z + (3 * -1 + 11z * -1)] = 3 + (7z + 1)
-1[3z + (-3 + -11z)] = 3 + (7z + 1)

Reorder the terms:
-1[-3 + 3z + -11z] = 3 + (7z + 1)

Combine like terms: 3z + -11z = -8z
-1[-3 + -8z] = 3 + (7z + 1)
[-3 * -1 + -8z * -1] = 3 + (7z + 1)
[3 + 8z] = 3 + (7z + 1)

Reorder the terms:
3 + 8z = 3 + (1 + 7z)

Remove parenthesis around (1 + 7z)
3 + 8z = 3 + 1 + 7z

Combine like terms: 3 + 1 = 4
3 + 8z = 4 + 7z

Solving
3 + 8z = 4 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
3 + 8z + -7z = 4 + 7z + -7z

Combine like terms: 8z + -7z = 1z
3 + 1z = 4 + 7z + -7z

Combine like terms: 7z + -7z = 0
3 + 1z = 4 + 0
3 + 1z = 4

Add '-3' to each side of the equation.
3 + -3 + 1z = 4 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = 4 + -3
1z = 4 + -3

Combine like terms: 4 + -3 = 1
1z = 1

Divide each side by '1'.
z = 1

Simplifying
z = 1

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